4a^2-8a-29=-8

Solution for 4a^2-8a-29=-8 equation:

4a^2-8a-29=-8

We move all terms to the left:

4a^2-8a-29-(-8)=0

We add all the numbers together, and all the variables

4a^2-8a-21=0

a = 4; b = -8; c = -21;
Δ = b2-4ac
Δ = -82-4·4·(-21)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-20}{2*4}=\frac{-12}{8}
=-1+1/2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+20}{2*4}=\frac{28}{8}
=3+1/2
$